3x(3x+1)-(1+9x^2)=0

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Solution for 3x(3x+1)-(1+9x^2)=0 equation:


Simplifying
3x(3x + 1) + -1(1 + 9x2) = 0

Reorder the terms:
3x(1 + 3x) + -1(1 + 9x2) = 0
(1 * 3x + 3x * 3x) + -1(1 + 9x2) = 0
(3x + 9x2) + -1(1 + 9x2) = 0
3x + 9x2 + (1 * -1 + 9x2 * -1) = 0
3x + 9x2 + (-1 + -9x2) = 0

Reorder the terms:
-1 + 3x + 9x2 + -9x2 = 0

Combine like terms: 9x2 + -9x2 = 0
-1 + 3x + 0 = 0
-1 + 3x = 0

Solving
-1 + 3x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 3x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 3x = 0 + 1
3x = 0 + 1

Combine like terms: 0 + 1 = 1
3x = 1

Divide each side by '3'.
x = 0.3333333333

Simplifying
x = 0.3333333333

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